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Hey there, math enthusiasts and tech explorers! You’ve just landed on math-linux.com - your go-to space where the fascinating worlds of mathematics and Linux intertwine. Whether you’re a student eager to dive deep into complex equations, a professional aiming to harness the power of Linux, or a curious soul intrigued by the blend of numbers and technology, you’ve just hit the jackpot!
Why Math-Linux?
Conceived and curated by me, Nadir Soualem, math-linux.com is a passion project born out of my love for making mathematics and Linux accessible, engaging, and downright fun. We live in a world where numbers shape our understanding and technology drives innovation. Here, we make that world both exciting and understandable.
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- Math Resources: Unpack complex math concepts with our easy-to-grasp tutorials, guides, and tips. It’s math made fun and functional!
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Latest articles
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1/x의 미분
함수 f(x)=1/x의 미분 f’(x)는 f’(x) = -1/x^2 (모든 0이 아닌 x에 대하여)
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x가 0에 접근할 때, sin x / x의 극한이 1임을 증명
x가 0에 접근할 때, sin x / x의 극한이 1임을 어떻게 증명할 수 있을까요?
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정현함수의 홀함수 성질 sin(-x)=-sin x
이 문서에서는 단위 원을 이용하여 정현함수 sin (-x) = - sin x가 홀함수임을 증명합니다.
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1/x の導関数
関数 f(x)=1/x の導関数 f’(x) は、f’(x) = -1/x^2 となります（すべての非ゼロ x に対して）
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xが0に近づくと、sin x / xの極限が1であることの証明
xが0に近づくと、sin x / xの極限が1であることの証明方法は？
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正弦は奇関数 sin(-x)=-sin x
この記事では、単位円を使用して、正弦関数 sin (-x) = - sin x が奇関数であることを証明します。
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当x趋近于0时证明sin x / x的极限等于1
如何证明当x趋近于0时sin x / x的极限等于1？
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1/x 的导数
函数 f(x)=1/x 的导数 f’(x) 为: f’(x) = -1/x^2 对所有非零 x
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正弦函数是奇函数 sin(-x)=-sin x
我们在这里证明正弦函数 sin (-x) = - sin x 是奇函数，使用单位圆。
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1/x এর অবক্ষেপণ
ফাংশন f(x)=1/x এর অবক্ষেপণ f’(x) হল: f’(x) = -1/x^2 সমস্ত শূন্য নয় এমন x এর জন্য